[om-list] Numbers as Operators
Mark Butler
butlerm at middle.net
Tue Oct 21 22:55:23 EDT 2003
Numbers as Operators
In standard number theory, a number is thought to be equivalent to the
set of all sets that have the specified number of members, i.e. those
that have the specified cardinality. However, in natural language,
numbers are not sets, but rather operators on sets.
A number operating on a set is similar in operation to a power set
operator operating on a set. A power set is the set of all the subsets
of a set. If you have a set with N elements, there are 2^N distinct
subsets. A number operating on a set produces a set containing all the
subsets of a set. So if I have the set "presidents of the United
States", and operate on it with the number "3", I get "three presidents
of the United States", or rather, one of the subsets of original set
that contain three members, {Washington Adams Jefferson}, {Truman
Kennedy Reagan}, or whatever.
In English, classes are always singular, and sets of unknown cardinality
are always plural. You can convert any class to a set simply by
changing it from singular to plural. "apple" is a class. "apples" is a
set. Singular definite expressions are always treated as classes, not
sets. "my apple" and "the apple" are classes with one instance. But
"my apples" and "the apples" are sets.
We say "Give me one of the apples" - "one of" is a set membership
operator and "apples" is a set. Alternatively, when we say "Give me one
apple", "apple" is a class and "one" is a singular class subset
operator, one that converts a class to a set (as necessary) and then
extracts one member, resulting in the same semantics as the first statement.
In English, it is not natural to have sets of sets, only sets of
classes. Sets in English always combine via union ("A, B, C and D, F,
G") if left to their own devices. If you want to do the equivalent of
sets of sets you have to convert to classes first, indeed any
conventional mathematical set is technically an English class because it
is treated as a singular expression. So "A, B, C" is an English set,
but {A, B, C} is an English class. A mathematical set of sets (e.g.
"{{A,B},{C}}") leads to Russell's Paradox when applied to the set of
all sets that do not contain themselves.
However, the same syntax read in English, as "the class of all classes
that are not subclasses of themselves" leads to no paradox, becauses no
class can ever contain a proper super class of itself, by definition -
no recursion, no paradox. That is an unfair change in semantics, but it
is nice to know that even though it implements an unusually
sophisticated arbitrary order logic, English is not easily prone to the
paradoxes that (regrettably) leveled Frege's set theoretic system.
- Mark
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